原创 有效利用指针数组，节省存储空间

如题所述，结合代码：

 #include<iostream.h>
#include<stdio.h>
void main()
{
 

 char name[5][20]={"xiongwei","luanjiyun","luanluqing","zhangyaping","xiongfuchang"};

//此时定义一个5行20列的字符型数组，即使未用，也开辟了内存空间。
 char *g=name[0];                             //定义一指向字符型指针，并初始化  
 cout<<"add address:"<<&g<<endl; 

 g=name[1];                                    
 cout<<"add address:"<<&g<<endl;
 
 g=name[2];                                    
 cout<<"add address:"<<g<<endl;

 g=name[3];                                    
 cout<<"add address:"<<g<<endl;

 g=name[4];                                    
 cout<<"add address:"<<g<<endl;

//可以比较以上输出的不同，前是指针的地址，后是指针所指向的字符串

 char *name1[5]={"xiongwei","luanjiyun","luanluqing","zhangyaping","xiongfuchang"};

//为了节省空间，可以定义一指针数组，分别指向每个字符串的首地址 

 for(int i="0";i<5;i++)
  cout<<"string#"<<(i+1)<<" is "<<name1<<endl;