原创 为什么主函数和中断函数不能调用同一函数？

Q. I get the error: function * appears in multiple call graphs: rooted at *
   What does this mean?

A. It means that there is a function which is being called from an interrupt
   and from main code and reentrancy is not supported by the compiler.
   Because the function is not reentrant, it leaves open the possibility
   of it being called from both locations at the same time. There are several
   possible ways to work around this:

1. If the compiler supports the "reentrant" qualifer, then define the function
   with this.

2. ROM space permitting, make two copies of the function but give them different
   names. One is only called by the interrupt, the other only by main code.

3. Rewrite the function such that it doesn't have any local variables or
   parameters. If the function doesn't have these, then it can be called from
   the interrupt and main code at the same time.

4. If you can guarantee that the function will not be called simultaneously, then
   you can use the #pragma interrupt_level directive. This is detailed in the
   user manuals, but in brief it is used like the following:

#pragma interrupt_level 1
void common_func(void)
{
   /* local variable definitions */

   /* code */
}

#pragma interrupt_level 1
void interrupt isr(void)
{
    common_func();
    /* more code */
}

void main(void)
{
   common_func();  /* gets called before interrupts are turned on */
   EI();    /* enable interrupts */
   /* more code */
}