原创 map容器->通过基于家族姓氏的查询输出该家族所有孩子的名字

问题:定义一个map对象,其元素的键是家族姓氏,而值存储该家族孩子名字的vector对象.为这个map容器输入至少6个条目.通过基于家族姓氏的查询检测你的程序,查询输出该家族所有孩子的名字

解决方案:

#include<iostream>

#include<map>

#include<vector>

#include<string>

using namespace std;

int main()

{

map<string,vetor<string>> children;

string surname,childname;

do{

cou<<"enter surname(Ctrl +Z to end):"<<endl;

cin>>surname;

if(!cin)

   break;

vector<string>chd;

pair<map<string,vector<string>>::iterator,bool> ret =

       children.insert(make_pair(surname,chd));

if(!ret.second){

   cout<<"repeated surname:"<<surname<<endl;

  continue;

}

cout<<"enter children's name(Ctrl + Z to end):"<<endl;

while(cin>>childname)

    ret.first->second.push_back(chlldname);

cin.clear();

}while(cin)

cin.clear();

cout<<"enter a surname to search:"<<endl;

cin>>surname;

map<string,vector<string>>::iterator iter = children.find(surname);

if(iter = = children.end())

  cout<<"no this surname:"<<surname<<endl;

else{

 cout<<"chlidren:"<<endl;

vector<string>:: iterator it = iter->second.begin();

while(it != iter->second.end())

  cout<<*it++<<endl;

}

return 0;

}